Resolver la ecuación $$ \frac{5x + 1}{5} + \frac{3x-2}{3} + \frac{2x-3}{2} = 0 $$
Usando $$ \frac{a+b}{c} = \frac{a}{c} + \frac{b}{c} $$
Aplicando a la ecuación tenemos: $$ \frac{5x}{5} + \frac{1}{5} + \frac{3x}{3} +\frac{2}{3} + \frac{2x}{3} - \frac{3}{2} = 0 \\ 3x = \frac{2}{3} + \frac{3}{2} - \frac{1}{5} \\ 3x = \frac{59}{30} x = \frac{59}{90} $$